Selfmate in 8

[Patrik]

Hi all,

I've searched through several problem databases but I couldn't find this one. It's a selfmate in 8, and though I get the idea (force the black bishops to c5/e4) I still can't find the solution.


Any ideas?

[papadoble]

I confess I did not try to solve but fed it to Popeye...
It turns out it is not too hard (easily said)

Hint1:
This is good (?) old mansuba style

Hint2:
Starts with 4 underpromotions

Solution:
1.f8=N+ Kd6 2.e8=N+ Kc6 3.c8=R+ Kb5 4.b8=R+ Kxa6 5.Ne4+ Ka7 6.Ra8+ Kb7 7.Nxc5+ Bxc5 8.Qe4+ Bxe4 #